Math Doubts

Division of Like Algebraic Terms

A mathematical operation of dividing an algebraic term by its like term is called the division of like algebraic terms.

Introduction

The division of any two like algebraic terms is expressed by displaying a division sign between them for dividing them. The quotient of the like algebraic terms is calculated by only finding the quotient of the numerical coefficients due to the same literal coefficient. Actually, the same literal coefficients of both like terms are cancelled in division. Hence, the literal coefficient can be ignored while doing the division with like terms in algebra.

$4xy^2$ and $-6xy^2$ are two like algebraic terms. Divide the term $4xy^2$ by $-6xy^2$ to find their quotient.

First step

Express the division of the like algebraic terms in mathematical form.
$4xy^2 \div (-6xy^2)$
$\implies$ $\dfrac{4xy^2}{-6xy^2}$

Second step

Factorize the each algebraic term as its numerical and literal coefficients.
$\implies \dfrac{4xy^2}{-6xy^2} \,=\, \dfrac{4 \times xy^2}{-6 \times xy^2}$
$\implies \dfrac{4xy^2}{-6xy^2} \,=\, \dfrac{4}{-6} \times \dfrac{xy^2}{xy^2}$

Third step

Find the quotient of the like algebraic terms by cancelling the literal coefficients, and then finding the quotient of the numerical coefficients.
$\require{cancel} \implies \dfrac{4xy^2}{-6xy^2} \,=\, \dfrac{4}{-6} \times \dfrac{\cancel{xy^2}}{\cancel{xy^2}}$
$\implies \dfrac{4xy^2}{-6xy^2} \,=\, \dfrac{4}{-6} \times 1$
$\implies \dfrac{4xy^2}{-6xy^2} \,=\, -\dfrac{4}{6}$
$\implies \require{cancel} \dfrac{4xy^2}{-6xy^2} \,=\, -\dfrac{\cancel{4}}{\cancel{6}}$
$\therefore \,\,\,\,\,\, \dfrac{4xy^2}{-6xy^2} \,=\, -\dfrac{2}{3}$

Thus, the division of any two like algebraic terms can be calculated in algebraic mathematics. Remember, the quotient of any two like terms is a rational number.

Examples

Observe the following examples to understand how to divide an algebraic term by its like term.

$(1) \,\,\,\,\,\,$ $\dfrac{a}{7a}$ $\,=\,$ $\require{cancel} \dfrac{1 \times \cancel{a}}{7 \times \cancel{a}}$ $\,=\,$ $\dfrac{1}{7}$

$(2) \,\,\,\,\,\,$ $\dfrac{3b^2}{6b^2}$ $\,=\,$ $\require{cancel} \dfrac{\cancel{3} \times \cancel{b^2}}{\cancel{6} \times \cancel{b^2}}$ $\,=\,$ $\dfrac{1}{2}$

$(3) \,\,\,\,\,\,$ $\dfrac{25cd^3}{cd^3}$ $\,=\,$ $\require{cancel} \dfrac{25 \times \cancel{cd^3}}{1 \times \cancel{cd^3}}$ $\,=\, 25$

$(4) \,\,\,\,\,\,$ $\dfrac{0.1e^2f^2}{0.01e^2f^2}$ $\,=\,$ $\require{cancel} \dfrac{\cancel{0.1} \times \cancel{e^2f^2}}{\cancel{0.01} \times \cancel{e^2f^2}}$ $\,=\, 10$

$(5) \,\,\,\,\,\,$ $\dfrac{56gh^2i^3j^4}{7gh^2i^3j^4}$ $\,=\,$ $\dfrac{\cancel{56} \times \cancel{gh^2i^3j^4}}{\cancel{7} \times \cancel{gh^2i^3j^4}}$ $\,=\, 8$

Math Doubts

A best free mathematics education website for students, teachers and researchers.

Maths Topics

Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.

Maths Problems

Learn how to solve the maths problems in different methods with understandable steps.

Learn solutions

Subscribe us

You can get the latest updates from us by following to our official page of Math Doubts in one of your favourite social media sites.

Copyright © 2012 - 2021 Math Doubts, All Rights Reserved