$\displaystyle \large \lim_{x \,\to\, \infty}{\normalsize {\Big(1+\dfrac{1}{x}\Big)}^{\displaystyle x}}$ $\,=\,$ $e$

The limit of $1+\dfrac{1}{x}$ raised to the power of $x$ as $x$ approaches infinity is equal to mathematical constant $e$.

In limits, the exponential functions similar to this function are often appeared. So, it’s considered as a standard result and used as a formula in calculus for evaluating the limits of exponential functions when its input tends to infinity.

This standard result of limits can also be written in terms of any variable.

$(1) \,\,\,$ $\displaystyle \large \lim_{g \,\to\, \infty}{\normalsize {\Big(1+\dfrac{1}{g}\Big)}^{\displaystyle g}}$ $\,=\,$ $e$

$(2) \,\,\,$ $\displaystyle \large \lim_{y \,\to\, \infty}{\normalsize {\Big(1+\dfrac{1}{y}\Big)}^{\displaystyle y}}$ $\,=\,$ $e$

Learn how to prove the limit of $x$-th power of binomial $1+\dfrac{1}{x}$ as $x$ approaches infinity is equal to $e$ in mathematics.

Latest Math Topics

Jul 20, 2023

Jun 26, 2023

Jun 23, 2023

Latest Math Problems

Jul 01, 2023

Jun 25, 2023

Copyright © 2012 - 2023 Math Doubts, All Rights Reserved