Math Doubts

Pythagorean identity of Cosecant and Cotangent functions

Formula

$\csc^2{\theta}-\cot^2{\theta} \,=\, 1$

The subtraction of square of cot function from square of co-secant function equals to one is called the Pythagorean identity of cosecant and co-tangent functions.

Introduction

In trigonometry, the cosecant and cotangent are two functions, which have a direct relationship between them in square form but it is derived from Pythagorean theorem. Hence, the relationship between cosecant and cot functions in square form is called the Pythagorean identity of co-secant and co-tangent functions.

right triangle
  1. $\Delta BAC$ is a right triangle in which its angle is denoted by the symbol theta.
  2. The cosecant and cotangent functions are written as $\csc{\theta}$ and $\cot{\theta}$ respectively.
  3. In the same way, their squares are written as $\csc^2{\theta}$ and $\cot^2{\theta}$ respectively in mathematical form.

The subtraction of the cot squared of angle from cosecant squared of angle is equal to one and it is called as the Pythagorean identity of cosecant and cotangent functions.

$\csc^2{\theta}-\cot^2{\theta} \,=\, 1$

Popular forms

The Pythagorean identity of cosecant and cot functions is also written popularly in two other forms.

  1. $\csc^2{x}-\cot^2{x} \,=\, 1$
  2. $\csc^2{A}-\cot^2{A} \,=\, 1$

Remember that the angle of a right triangle can be denoted by any symbol but the relation between cosecant and cot functions have to be written in that symbol.

Proof

Learn how to prove the Pythagorean identity of cosecant and cot functions in mathematical form by geometrical method.

Math Doubts

A best free mathematics education website for students, teachers and researchers.

Maths Topics

Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.

Maths Problems

Learn how to solve the maths problems in different methods with understandable steps.

Learn solutions

Subscribe us

You can get the latest updates from us by following to our official page of Math Doubts in one of your favourite social media sites.

Copyright © 2012 - 2022 Math Doubts, All Rights Reserved