Math Doubts

Pythagorean identity of Secant and Tangent functions

Formula

$\sec^2{\theta}-\tan^2{\theta} \,=\, 1$

The subtraction of square of tan function from square of secant function equals to one is called the Pythagorean identity of secant and tangent functions.

Introduction

In trigonometry, the secant and tangent are two functions, and they have a direct relation between them in square form but their relationship is derived from Pythagorean theorem. Therefore, the relation between secant and tangent functions in square form is called the Pythagorean identity of secant and tangent functions.

right triangle
  1. $\Delta CAB$ is a right triangle and its angle is denoted by the symbol theta.
  2. The secant and tangent functions are written as $\sec{\theta}$ and $\tan{\theta}$ respectively.
  3. Similarly, their squares are written as $\sec^2{\theta}$ and $\tan^2{\theta}$ respectively in mathematical form.

The subtraction of the tan squared of angle from secant squared of angle is equal to one and it is called as the Pythagorean identity of secant and tangent functions.

$\sec^2{\theta}-\tan^2{\theta} \,=\, 1$

Popular forms

The Pythagorean identity of secant and tan functions can also be written popularly in two other forms.

  1. $\sec^2{x}-\tan^2{x} \,=\, 1$
  2. $\sec^2{A}-\tan^2{A} \,=\, 1$

Remember, the angle of a right triangle can be represented by any symbol but the relationship between secant and tan functions must be written in that symbol.

Proof

Learn how to prove the Pythagorean identity of secant and tan functions in mathematical form by geometrical method.

Math Doubts

A best free mathematics education website that helps students, teachers and researchers.

Maths Topics

Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.

Maths Problems

A math help place with list of solved problems with answers and worksheets on every concept for your practice.

Learn solutions

Subscribe us

You can get the latest updates from us by following to our official page of Math Doubts in one of your favourite social media sites.

Copyright © 2012 - 2022 Math Doubts, All Rights Reserved