The logarithm of one to any base number is equal to zero as per the logarithm of one identity.

$\log_{b}{(1)} \,=\, 0$

Now, let’s learn how to prove the logarithm of one rule in algebraic form.

Let $b$ be a literal and represents a base quantity in algebraic form. The logarithm of one to base quantity $b$ is written mathematically as follows.

$\log_{b}{(1)}$

According to the zero power rule, the base quantity raised to the power of zero is equal to one. In this case, the base quantity is denoted by $b$. Therefore, the zero power law can be written in mathematics as follows.

$b^0 \,=\, 1$

The logarithmic system is an inverse operation of the exponential system. It means the two concepts have mathematical relationship and it can be used to prove this logarithmic identity in mathematics. According to the mathematical relation between the exponents and logarithms.

$1 \,=\, b^0$ $\,\, \Leftrightarrow \,\,$ $\log_{b}{(1)} \,=\, 0$

Therefore, it is proved that the logarithm of one to the base $b$ is equal to zero.

$\therefore \,\,\,$ $\log_{b}{(1)} \,=\, 0$

Latest Math Topics

Dec 13, 2023

Jul 20, 2023

Jun 26, 2023

Latest Math Problems

Jan 30, 2024

Oct 15, 2023

Copyright © 2012 - 2023 Math Doubts, All Rights Reserved