$\displaystyle \int{\csc{x}\cot{x} \,}dx \,=\, -\csc{x}+c$
Assume, $x$ as a variable, and represents an angle of a right triangle. The cosecant and cotangent functions are written in terms of $x$ as $\csc{x}$ or $\operatorname{cosec}{x}$ and $\cot{x}$ respectively. The indefinite integral of product of $\csc{x}$ and $\cot{x}$ functions with respect to $x$ is written in the following mathematical form in integral calculus.
$\displaystyle \int{\csc{x}\cot{x} \,} dx$
The indefinite integration of product of cosecant and cot functions with respect to $x$ is equal to the sum of negative cosecant function and an integral constant.
$\displaystyle \int{\csc{x}\cot{x} \,}dx \,=\, -\csc{x}+c$
The integral of product of cosecant and cot functions formula can be written in terms of any variable in integral calculus.
$(1) \,\,\,$ $\displaystyle \int{\csc{(k)}\cot{(k)} \,}dk \,=\, -\csc{(k)}+c$
$(2) \,\,\,$ $\displaystyle \int{\csc{(m)}\cot{(m)} \,}dm \,=\, -\csc{(m)}+c$
$(3) \,\,\,$ $\displaystyle \int{\csc{(z)}\cot{(z)} \,}dz \,=\, -\csc{(z)}+c$
Learn how to derive the integration rule for the product of cosecant and cotangent functions in integral calculus.
A best free mathematics education website for students, teachers and researchers.
Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.
Learn how to solve the maths problems in different methods with understandable steps.
Copyright © 2012 - 2022 Math Doubts, All Rights Reserved