Math Doubts

Proof of Quotient law of Logarithms

Formula

$\log_{b}{\Big(\dfrac{m}{n}\Big)}$ $\,=\,$ $\log_{b}{m}-\log_{b}{n}$

The quotient rule is another most useful logarithmic identity, which states that logarithm of quotient of two quotients is equal to difference of their logs. The property of quotient rule can be derived in algebraic form on the basis of relation between exponents and logarithms, and quotient rule of exponents.

Express quantities in Exponential form

$m$ and $n$ are two quantities, and express both quantities in product form on the basis of another quantity $b$.

The total multiplying factors of $b$ is $x$ and the product of them is equal to $m$.

$m$ $\,=\,$ $\underbrace{b \times b \times b \times \ldots \times b}_{\displaystyle x \, factors}$

$\implies m \,=\, b^{\displaystyle x}$

In the same way, the total multiplying factors of $b$ is $y$ and the product of them is equal to $n$.

$n$ $\,=\,$ $\underbrace{b \times b \times b \times \ldots \times b}_{\displaystyle y \, factors}$

$\implies n \,=\, b^{\displaystyle y}$

Thus, the two quantities are written in exponential notation as follows.

$(1) \,\,\,\,\,\,$ $m \,=\, b^{\displaystyle x}$

$(2) \,\,\,\,\,\,$ $n \,=\, b^{\displaystyle y}$

Write quantities in logarithmic form

On the basis of mathematical relation between exponents and logarithms, the quantities in exponential form can be written in logarithmic form as follows.

$(1) \,\,\,\,\,\,$ $b^{\displaystyle x} \,=\, m$ $\,\, \Leftrightarrow \,\,$ $\log_{b}{m} = x$

$(2) \,\,\,\,\,\,$ $b^{\displaystyle y} \,=\, n$ $\,\,\,\, \Leftrightarrow \,\,$ $\log_{b}{n} = y$

Quotient of the quantities by division

Divide the quantity $m$ by $n$ to get the quotient of them mathematically.

$\dfrac{m}{n}$

Actually, the values of the quantities $m$ and $n$ in exponential notation are $b^{\displaystyle x}$ and $b^{\displaystyle y}$ respectively.

$\implies \dfrac{m}{n} \,=\, \dfrac{b^{\displaystyle x}}{b^{\displaystyle y}}$

According to the quotient rule of exponents, the quotient of exponential terms whose base is same, is equal to the base is raised to the power of difference of exponents.

$\implies \dfrac{m}{n} \,=\, b^{\,({\displaystyle x}\,-\,{\displaystyle y})}$

Transform quantity from exponential to logarithm form

Take $d = x-y$ and $q = \dfrac{m}{n}$. Then, write the equation in terms of $d$ and $q$.

$\implies q = b^{\displaystyle d}$

Now write the equation in log form.

$\implies \log_{b}{q} = d$

Replace the original values of the quantities $d$ and $q$.

$\implies \log_{b}{\Big(\dfrac{m}{n}\Big)} = x-y$

Get the logarithmic property

The logarithm of quotient of two quantities $m$ and $n$ to the base $b$ is equal to difference of the quantities $x$ and $y$.

In fact, $x \,=\, \log_{b}{m}$ and $y \,=\, \log_{b}{n}$. So, replace them to obtain the property for the quotient rule of logarithms.

$\,\,\, \therefore \,\,\,\,\,\, \log_{b}{\Big(\dfrac{m}{n}\Big)}$ $\,=\,$ $\log_{b}{m}-\log_{b}{n}$

It has proved that the logarithm of quotient of two quantities to a base is equal to difference their logs to the same base. The fundamental law is also called as division rule of logarithms and used as a formula in mathematics.

Math Doubts

A best free mathematics education website for students, teachers and researchers.

Maths Topics

Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.

Maths Problems

Learn how to solve the maths problems in different methods with understandable steps.

Learn solutions

Subscribe us

You can get the latest updates from us by following to our official page of Math Doubts in one of your favourite social media sites.

Copyright © 2012 - 2021 Math Doubts, All Rights Reserved