$\displaystyle \int{\sec{x}\tan{x} \,}dx \,=\, \sec{x}+c$

Take, $x$ as a variable, and represents an angle of a right triangle. The secant and tangent functions are written in terms of $x$ as $\sec{x}$ and $\tan{x}$ respectively. The indefinite integral of product of $\sec{x}$ and $\tan{x}$ functions with respect to $x$ is written in integral calculus as follows.

$\displaystyle \int{\sec{x}\tan{x} \,} dx$

The integration of product of secant and tan functions with respect to $x$ is equal to the sum of secant function and the constant of integration.

$\displaystyle \int{\sec{x}\tan{x} \,}dx \,=\, \sec{x}+c$

The indefinite integral of product of secant and tan functions formula can be written in terms of any variable in calculus.

$(1) \,\,\,$ $\displaystyle \int{\sec{(j)}\tan{(j)} \,}dj \,=\, \sec{(j)}+c$

$(2) \,\,\,$ $\displaystyle \int{\sec{(q)}\tan{(q)} \,}dq \,=\, \sec{(q)}+c$

$(3) \,\,\,$ $\displaystyle \int{\sec{(y)}\tan{(y)} \,}dy \,=\, \sec{(y)}+c$

Learn how to derive the integration rule for the product of secant and tangent functions in integral calculus.

Latest Math Topics

Jul 20, 2023

Jun 26, 2023

Jun 23, 2023

Latest Math Problems

Jul 01, 2023

Jun 25, 2023

Copyright © 2012 - 2023 Math Doubts, All Rights Reserved