Math Doubts

Difference rule of Integration

Formula

$\displaystyle \int{\Big(f(x)-g(x)\Big)\,}dx$ $\,=\,$ $\displaystyle \int{f(x)\,}dx$ $-$ $\displaystyle \int{g(x)\,}dx$

The integral of difference of functions equals to difference of their integrals is called the difference rule of integration.

Introduction

When $f(x)$ and $g(x)$ represent two functions in $x$, the indefinite integral of every function with respect to $x$ is written in the following mathematical form.

$(1)\,\,\,$ $\displaystyle \int{f(x)\,}dx$

$(2)\,\,\,$ $\displaystyle \int{g(x)\,}dx$

The difference of two functions is written as $f(x)-g(x)$ in mathematical form. The indefinite integral of difference of the functions with respect $x$ is written as follows.

$\displaystyle \int{\Big(f(x)-g(x)\Big)\,}dx$

As per integral calculus, the integral of difference of any two functions is equal to the difference of their integrals. The property can be expressed as equation in mathematical form and it is called as the difference rule of integration.

$\implies$ $\displaystyle \int{\Big(f(x)-g(x)\Big)\,}dx$ $\,=\,$ $\displaystyle \int{f(x)\,}dx$ $-$ $\displaystyle \int{g(x)\,}dx$

Example

Evaluate $\displaystyle \int{(1-2x)\,}dx$

Now, use the integral difference rule for evaluating the integration of difference of the functions.

$=\,\,\,$ $\displaystyle \int{1\,}dx-\int{2x\,}dx$

$=\,\,\,$ $\displaystyle \int{1\,}dx-2\int{x\,}dx$

$=\,\,\,$ $x+c_1-2\Big(\dfrac{x^2}{2}+c_2\Big)$

$=\,\,\,$ $x+c_1-2 \times \dfrac{x^2}{2}-2 \times c_2$

$=\,\,\,$ $x+c_1-\dfrac{2x^2}{2}-2c_2$

$=\,\,\,$ $\require{cancel} x+c_1-\dfrac{\cancel{2}x^2}{\cancel{2}}-2c_2$

$=\,\,\,$ $x+c_1-x^2-2c_2$

$=\,\,\,$ $x-x^2+c_1-2c_2$

$=\,\,\,$ $x-x^2+c$

Proof

Learn how to derive the difference rule of indefinite integration in integral calculus.

Math Doubts

A best free mathematics education website for students, teachers and researchers.

Maths Topics

Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.

Maths Problems

Learn how to solve the maths problems in different methods with understandable steps.

Learn solutions

Subscribe us

You can get the latest updates from us by following to our official page of Math Doubts in one of your favourite social media sites.

Copyright © 2012 - 2021 Math Doubts, All Rights Reserved