$\dfrac{d}{dx}{\, \cosh{x}} \,=\, \sinh{x}$
The hyperbolic cosine function appears in differentiation. So, we have to know the derivative of hyperbolic cosine function in differential calculus.
The hyperbolic cosine is written as $\cosh{(x)}$ in mathematical form if $x$ is considered as a variable. The derivative or differentiation of $\cosh{x}$ with respect to $x$ is expressed as $\dfrac{d}{dx}{\, \cosh{x}}$ mathematically in calculus. It is actually equal to the $\sinh{x}$.
$\dfrac{d}{dx}{\, \sinh{x}}$ $\,=\,$ $\cosh{x}$
The variable can be denoted by symbol but the derivative of the hyperbolic cosine function must be expressed in terms of the respective variable. You must remember it while dealing the differential calculus.
$(1) \,\,\,$ $\dfrac{d}{dg}{\, \cosh{(g)}}$ $\,=\,$ $\sinh{(g)}$
$(2) \,\,\,$ $\dfrac{d}{dp}{\, \cosh{(p)}}$ $\,=\,$ $\sinh{(p)}$
$(3) \,\,\,$ $\dfrac{d}{dt}{\, \cosh{(t)}}$ $\,=\,$ $\sinh{(t)}$
The above example understands you that the differentiation of hyperbolic cosine is equal to hyperbolic sine.
Learn how to derive the derivative of hyperbolic cosine formula in differential calculus.
List of most recently solved mathematics problems.
Learn how to solve easy to difficult mathematics problems of all topics in various methods with step by step process and also maths questions for practising.