$\dfrac{d}{dx}{\, (\tan{x})} \,=\, \sec^2{x}$

The derivative or differentiation of tan function with respect to a variable is equal to square of the secant function. It is read as the derivative of $\tan{x}$ with respect to $x$ is equal to $\sec^2{x}$.

If $x$ is taken as a variable, then the tangent function is written as $\tan{x}$ in mathematics. The derivative of the tan function with respect to $x$ is written mathematically in differential calculus as follows.

$\dfrac{d}{dx}{\, (\tan{x})}$

The derivative of $\tan{x}$ with respect to $x$ is also be expressed as $\dfrac{d{\,(\tan{x})}}{dx}$. It can also be written as ${(\tan{x})}’$ simply in calculus.

The differentiation of the tan function can be written in terms of any variable.

$(1) \,\,\,$ $\dfrac{d}{dg}{\, (\tan{g})} \,=\, \sec^2{g}$

$(2) \,\,\,$ $\dfrac{d}{dz}{\, (\tan{z})} \,=\, \sec^2{z}$

Learn how to derive the differentiation of the tan function from first principle in differential calculus.

Latest Math Topics

Latest Math Problems

Email subscription

Learn how to solve easy to difficult mathematics problems of all topics in various methods with step by step process and also maths questions for practising.