$\dfrac{d}{dx}{\, (\sec{x})} \,=\, \sec{x}\tan{x}$

The differentiation or derivative of secant function with respect to a variable is equal to the product of secant and tangent functions. This derivative formula is read as the derivative of $\sec{x}$ function with respect to $x$ is equal to the product of $\sec{x}$ and $\tan{x}$.

Assume $x$ is a variable, then the secant function is written as $\sec{x}$ in mathematical form as per trigonometry. The derivative of the secant function with respect to $x$ is written as the following mathematical form.

$\dfrac{d}{dx}{\, (\sec{x})}$

In mathematics, the differentiation of the $\sec{x}$ function with respect to $x$ can be written as $\dfrac{d{\,(\sec{x})}}{dx}$ and also simply written as ${(\sec{x})}’$.

The differentiation of the secant function can be written in terms of any variable.

$(1) \,\,\,$ $\dfrac{d}{dh}{\, (\sec{h})} \,=\, \sec{h}\tan{h}$

$(2) \,\,\,$ $\dfrac{d}{dw}{\, (\sec{w})} \,=\, \sec{w}\tan{w}$

$(3) \,\,\,$ $\dfrac{d}{dy}{\, (\sec{y})} \,=\, \sec{y}\tan{y}$

Learn how to prove the derivative of the secant function by first principle in differential calculus.

Latest Math Topics

Latest Math Problems

Email subscription

Math Doubts is a best place to learn mathematics and from basics to advanced scientific level for students, teachers and researchers.
Know more

Learn how to solve easy to difficult mathematics problems of all topics in various methods with step by step process and also maths questions for practising.