The cot value when angle of a right triangle equals to $90^°$ is called cot of angle $90$ degrees and it is written as $\cot{(90^°)}$ mathematically in sexagesimal system.

$\cot{(90^°)} \,=\, 0$

The exact value of $\cot{(90^°)}$ is zero mathematically.

The $\cot{(90^°)}$ is written in different ways in alternative form. In other words, it is written as $\cot{\Big(\dfrac{\pi}{2}\Big)}$ in circular system and also written as $\cot{(100^g)}$ in centesimal system.

$(1) \,\,\,$ $\cot{\Big(\dfrac{\pi}{2}\Big)} \,=\, 0$

$(2) \,\,\,$ $\cot{(100^g)} \,=\, 0$

You learnt that the value of $\cot{\Big(\dfrac{\pi}{2}\Big)}$ is zero exactly. Now, it is time to learn how the value of $\cot{(100^g)}$ is zero exactly in trigonometry.

Latest Math Topics

Apr 18, 2022

Apr 14, 2022

Apr 05, 2022

Mar 18, 2022

Mar 05, 2022

Latest Math Problems

Apr 06, 2022

Mar 22, 2022

A best free mathematics education website for students, teachers and researchers.

Learn each topic of the mathematics easily with understandable proofs and visual animation graphics.

Learn how to solve the maths problems in different methods with understandable steps.

Copyright © 2012 - 2021 Math Doubts, All Rights Reserved