# Evaluate $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{\sqrt{x-b}-\sqrt{a-b}}{x^2-a^2}}$

A mathematical expression is formed in terms of literals $x$, $a$ and $b$. In this problem, $x$ is a variable but $a$ and $b$ are constants, and we have to evaluate the limit of the function as $x$ approaches $a$.

$\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{\sqrt{x-b}-\sqrt{a-b}}{x^2-a^2}}$

### Evaluate the Limit by Direct substitution

Now, let us try the basic mathematical approach the direct substitution method for evaluating the limit of the function as $x$ approaches $a$.

$=\,\,\,$ $\dfrac{\sqrt{a-b}-\sqrt{a-b}}{a^2-a^2}$

$=\,\,\,$ $\dfrac{0}{0}$

According to the direct substitution method, the limit of the given function is indeterminate as $x$ closer to $a$. Hence, we have to evaluate the limit of the function in another mathematical approach.

The expression in the numerator is an irrational function and it is also a main reason for the indeterminate form in this limit problem. So, the expression in the numerator should be rationalized.

### Try to Use the Rationalization method

So, let us try the rationalizing method for avoiding the indeterminate form.

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \Bigg(\dfrac{\sqrt{x-b}-\sqrt{a-b}}{x^2-a^2}}$ $\times$ $\dfrac{\sqrt{x-b}+\sqrt{a-b}}{\sqrt{x-b}+\sqrt{a-b}}\Bigg)$

### Simplify the Mathematical expression

Now, focus on simplifying the mathematical expression for evaluating the limit of the given function. The product of the fractional functions can be simplified by the multiplication of fractions.

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{\Big(\sqrt{x-b}-\sqrt{a-b}\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

The product of the expressions in the numerator can be simplified by the difference rule of squares.

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{\Big(\sqrt{x-b}\Big)^2-\Big(\sqrt{a-b}\Big)^2}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x-b-(a-b)}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x-b-a+b}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x-b+b-a}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\require{cancel} \displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x-\cancel{b}+\cancel{b}-a}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x-a}{\Big(x^2-a^2\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

Now, factorize the difference of squares by the same difference of squares formula.

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x-a}{\Big(x-a\Big)\Big(x+a\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{\cancel{x-a}}{\Big(\cancel{x-a}\Big)\Big(x+a\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

$=\,\,\,$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{1}{\Big(x+a\Big)\Big(\sqrt{x-b}+\sqrt{a-b}\Big)}}$

### Evaluate the Limit of the function

In the previous step, we have successfully simplified the mathematical expression and it cannot be simplified further. Therefore, we can now evaluate the limit of the function as $x$ tends to $a$. Now, the limit of the function can be evaluated by the direct substitution method.

$=\,\,\,$ $\dfrac{1}{\Big(a+a\Big)\Big(\sqrt{a-b}+\sqrt{a-b}\Big)}$

$=\,\,\,$ $\dfrac{1}{\Big(2a\Big)\Big(2\sqrt{a-b}\Big)}$

$=\,\,\,$ $\dfrac{1}{2a \times 2\sqrt{a-b}}$

$=\,\,\,$ $\dfrac{1}{4a\sqrt{a-b}}$

Latest Math Topics
Jun 26, 2023

###### Math Questions

The math problems with solutions to learn how to solve a problem.

Learn solutions

###### Math Worksheets

The math worksheets with answers for your practice with examples.

Practice now

###### Math Videos

The math videos tutorials with visual graphics to learn every concept.

Watch now

###### Subscribe us

Get the latest math updates from the Math Doubts by subscribing us.

Learn more

A free math education service for students to learn every math concept easily, for teachers to teach mathematics understandably and for mathematicians to share their maths researching projects.

Copyright © 2012 - 2023 Math Doubts, All Rights Reserved