Math Doubts

Is 2 a prime number?

The number two is a second natural number and let’s find whether the natural number $2$ is a prime number or not by the fundamental definition of a prime number.

is 2 a prime number?

According to the definition of a prime number, let’s observe what happens when the natural number $2$ is divided by both one and itself.

Divide the number 2 by 1

Firstly, let’s divide the natural number $2$ by the natural number $1$.

$2 \div 1$

$\implies$ $\dfrac{2}{1} \,=\, 2$

The natural number $2$ is completely divided by the $1$. So, the quotient of $2$ divided by $1$ is $2$. It clears that there is a chance for the natural number $2$ to become a prime number.

Divide the number 2 by itself

Now, let’s divide the natural number $2$ by the same natural number.

$2 \div 2$

$\implies$ $\dfrac{2}{2} \,=\, 1$

The natural number $2$ is completely divided by itself and the quotient of $2$ divided by $2$ is equal to $1$.

Conclusion

  1. The number $2$ is completely divided by the number $1$.
  2. The number $2$ is also completely divided by the same number.

It clears that the number $2$ is divisible only by one and itself. Therefore, the number $2$ can only be expressed as a product of one and itself.

$\implies$ $2$ $\,=\,$ $1 \times 2$

The number $2$ has only two factors and they are $1$ and $2$. It proves that the number $2$ is a prime number and it is a first prime number in the natural numbers.

Math Questions

The math problems with solutions to learn how to solve a problem.

Learn solutions

Math Worksheets

The math worksheets with answers for your practice with examples.

Practice now

Math Videos

The math videos tutorials with visual graphics to learn every concept.

Watch now

Subscribe us

Get the latest math updates from the Math Doubts by subscribing us.

Learn more

Math Doubts

A free math education service for students to learn every math concept easily, for teachers to teach mathematics understandably and for mathematicians to share their maths researching projects.

Copyright © 2012 - 2023 Math Doubts, All Rights Reserved